Whether an isosceles triangle is acute, right or obtuse depends only on the angle at its apex. In Euclidean geometry, the base angles can not be obtuse (greater than 90°) or right (equal to 90°) because their measures would sum to at least 180°, the total of all angles in any Euclidean triangle. Since a triangle is obtuse or right if and only if one of its angles is obtuse or right, respectively, an isosceles triangle is obtuse, right or acute if and only if its apex angle is respectively obtuse, right or acute. In Edwin Abbott's book Flatland, this classification of shapes was used as a satire of social hierarchy: isosceles triangles represented the working class, with acute isosceles triangles higher in the hierarchy than right or obtuse isosceles triangles.

As well as the isosceles right triangle, several other specific shapes of isosceles triangles have been studied. These include the Calabi triangle (a triangle with three congruent inscribed squares), the golden triangle and golden gnomon (two isosceles triangles whose sides and base are in the golden ratio), the 80-80-20 triangle appearing in the Langley's Adventitious Angles puzzle, and the 30-30-120 triangle of the triakis triangular tiling. Five Catalan solids, the triakis tetrahedron, triakis octahedron, tetrakis hexahedron, pentakis dodecahedron, and triakis icosahedron, each have isosceles-triangle faces, as do infinitely many pyramids and bipyramids.

For any isosceles triangle, the following six line segments coincide:

• the altitude, a line segment from the apex perpendicular to the base,
• the angle bisector from the apex to the base,
• the median from the apex to the midpoint of the base,
• the perpendicular bisector of the base within the triangle,
• the segment within the triangle of the unique axis of symmetry of the triangle, and
• the segment within the triangle of the Euler line of the triangle, except when the triangle is equilateral.

Their common length is the height ${\displaystyle h}$ of the triangle. If the triangle has equal sides of length ${\displaystyle a}$ and base of length ${\displaystyle b}$, the general triangle formulas for the lengths of these segments all simplify to

${\displaystyle h={\sqrt {a^{2}-{\frac {b^{2}}{4}}}}.}$

This formula can also be derived from the Pythagorean theorem using the fact that the altitude bisects the base and partitions the isosceles triangle into two congruent right triangles.

The Euler line of any triangle goes through the triangle's orthocenter (the intersection of its three altitudes), its centroid (the intersection of its three medians), and its circumcenter (the intersection of the perpendicular bisectors of its three sides, which is also the center of the circumcircle that passes through the three vertices). In an isosceles triangle with exactly two equal sides, these three points are distinct, and (by symmetry) all lie on the symmetry axis of the triangle, from which it follows that the Euler line coincides with the axis of symmetry. The incenter of the triangle also lies on the Euler line, something that is not true for other triangles. If any two of an angle bisector, median, or altitude coincide in a given triangle, that triangle must be isosceles.

The area ${\displaystyle T}$ of an isosceles triangle can be derived from the formula for its height, and from the general formula for the area of a triangle as half the product of base and height:

${\displaystyle T={\frac {b}{4}}{\sqrt {4a^{2}-b^{2}}}.}$

The same area formula can also be derived from Heron's formula for the area of a triangle from its three sides. However, applying Heron's formula directly can be numerically unstable for isosceles triangles with very sharp angles, because of the near-cancellation between the semiperimeter and side length in those triangles.

If the apex angle ${\displaystyle (\theta )}$ and leg lengths ${\displaystyle (a)}$ of an isosceles triangle are known, then the area of that triangle is:

${\displaystyle T={\frac {1}{2}}a^{2}\sin \theta .}$

This is a special case of the general formula for the area of a triangle as half the product of two sides times the sine of the included angle.

The perimeter ${\displaystyle p}$ of an isosceles triangle with equal sides ${\displaystyle a}$ and base ${\displaystyle b}$ is just

${\displaystyle p=2a+b.}$

As in any triangle, the area ${\displaystyle T}$ and perimeter ${\displaystyle p}$ are related by the isoperimetric inequality

${\displaystyle p^{2}>12{\sqrt {3}}T.}$

This is a strict inequality for isosceles triangles with sides unequal to the base, and becomes an equality for the equilateral triangle. The area, perimeter, and base can also be related to each other by the equation

${\displaystyle 2pb^{3}-p^{2}b^{2}+16T^{2}=0.}$

If the base and perimeter are fixed, then this formula determines the area of the resulting isosceles triangle, which is the maximum possible among all triangles with the same base and perimeter. On the other hand, if the area and perimeter are fixed, this formula can be used to recover the base length, but not uniquely: there are in general two distinct isosceles triangles with given area ${\displaystyle T}$ and perimeter ${\displaystyle p}$. When the isoperimetric inequality becomes an equality, there is only one such triangle, which is equilateral.

If the two equal sides have length ${\displaystyle a}$ and the other side has length ${\displaystyle b}$, then the internal angle bisector ${\displaystyle t}$ from one of the two equal-angled vertices satisfies

${\displaystyle {\frac {2ab}{a+b}}>t>{\frac {ab{\sqrt {2}}}{a+b}}}$

as well as

${\displaystyle t<{\frac {4a}{3}};}$

and conversely, if the latter condition holds, an isosceles triangle parametrized by ${\displaystyle a}$ and ${\displaystyle t}$ exists.

The Steiner–Lehmus theorem states that every triangle with two angle bisectors of equal lengths is isosceles. It was formulated in 1840 by C. L. Lehmus. Its other namesake, Jakob Steiner, was one of the first to provide a solution. Although originally formulated only for internal angle bisectors, it works for many (but not all) cases when, instead, two external angle bisectors are equal. The 30-30-120 isosceles triangle makes a boundary case for this variation of the theorem, as it has four equal angle bisectors (two internal, two external).

The inradius and circumradius formulas for an isosceles triangle may be derived from their formulas for arbitrary triangles. The radius of the inscribed circle of an isosceles triangle with side length ${\displaystyle a}$, base ${\displaystyle b}$, and height ${\displaystyle h}$ is:

${\displaystyle {\frac {2ab-b^{2}}{4h}}.}$

The center of the circle lies on the symmetry axis of the triangle, this distance above the base. An isosceles triangle has the largest possible inscribed circle among the triangles with the same base and apex angle, as well as also having the largest area and perimeter among the same class of triangles.

The radius of the circumscribed circle is:

${\displaystyle {\frac {a^{2}}{2h}}.}$

The center of the circle lies on the symmetry axis of the triangle, this distance below the apex.

For any isosceles triangle, there is a unique square with one side collinear with the base of the triangle and the opposite two corners on its sides. The Calabi triangle is a special isosceles triangle with the property that the other two inscribed squares, with sides collinear with the sides of the triangle, are of the same size as the base square. A much older theorem, preserved in the works of Hero of Alexandria, states that, for an isosceles triangle with base ${\displaystyle b}$ and height ${\displaystyle h}$, the side length of the inscribed square on the base of the triangle is

${\displaystyle {\frac {bh}{b+h}}.}$

For any integer ${\displaystyle n\geq 4}$, any triangle can be partitioned into ${\displaystyle n}$ isosceles triangles. In a right triangle, the median from the hypotenuse (that is, the line segment from the midpoint of the hypotenuse to the right-angled vertex) divides the right triangle into two isosceles triangles. This is because the midpoint of the hypotenuse is the center of the circumcircle of the right triangle, and each of the two triangles created by the partition has two equal radii as two of its sides. Similarly, an acute triangle can be partitioned into three isosceles triangles by segments from its circumcenter, but this method does not work for obtuse triangles, because the circumcenter lies outside the triangle.

Generalizing the partition of an acute triangle, any cyclic polygon that contains the center of its circumscribed circle can be partitioned into isosceles triangles by the radii of this circle through its vertices. The fact that all radii of a circle have equal length implies that all of these triangles are isosceles. This partition can be used to derive a formula for the area of the polygon as a function of its side lengths, even for cyclic polygons that do not contain their circumcenters. This formula generalizes Heron's formula for triangles and Brahmagupta's formula for cyclic quadrilaterals.

Either diagonal of a rhombus divides it into two congruent isosceles triangles. Similarly, one of the two diagonals of a kite divides it into two isosceles triangles, which are not congruent except when the kite is a rhombus.